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7g^2-3=-7g
We move all terms to the left:
7g^2-3-(-7g)=0
We get rid of parentheses
7g^2+7g-3=0
a = 7; b = 7; c = -3;
Δ = b2-4ac
Δ = 72-4·7·(-3)
Δ = 133
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{133}}{2*7}=\frac{-7-\sqrt{133}}{14} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{133}}{2*7}=\frac{-7+\sqrt{133}}{14} $
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